2D list in C++ STL (Defining and Sorting)
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In this article, we will begin with a brief recap of what lists are, followed by an introduction to 2-dimensional lists (2D list), where we shall explore creating and defining 2D lists in C++ STL and sorting them.
Table of content:
- Lists in C++ STL
- 2D list in C++ STL
- Sorting individual list elements of the 2D list
- Sorting the entire 2-D list by comparing elements from individual lists
- Sorting the 2-D list according to the value of its elements present at a particular index
Let us begin!
Lists in C++ STL
std::list
belongs to the Standard Template Library (STL) provided by C++. In contrast to vectors and arrays which provide contiguous memory allocation, lists are sequence containers with non-contiguous memory allocation i.e. the items in a list are stored all over the memory disk and connected via forward and backward pointers.
Due to this-
- Traversing a list is a slow task.
- Elements cannot be accessed quickly and randomly.
- However, insertion and deletion can be achieved in constant time complexity once the position is found.
The syntax for declaring a list is as follows:
list<int> list1;
The data type of the elements (here int
) is declared inside the <>
. To make a list of strings, just replace int
with string
. This can be done for all data-types.
To work with lists, include the header file #include <list>
or #include <bits/stdc++.h>
.
Quick question:
Which data structure does a list in C++ implement?
2D list in C++ STL
The concept of 2-D lists is similar to working with two-dimensional arrays or vectors. In two-dimensional lists, we basically make a list of lists, i.e. lists are nested inside one another. They can be declared in code as
list <list <int>> list2;
For initializing it, use the assignment =
operator. Ex.
list <list <int>> list2= {{1,2,3},{7,2},{5,3,1}};
We can also initalise a 2-d list using inputs from stdin
by using 2 nested for
loops and and deciding the size of each list. For traversal and displaying the values in the list, we still use 2 nested for
loops. Let us see the code snippets-
int main()
{
list<list<int>> list1(2);
cout<<"enter values:"<<endl;
for( auto i=0;i<2;i++)
//here, 2 is the size of the overall list.
{
list<int> list2; int a;
for(auto j1=0;j1<2;j1++)
// here, 2 is the size of each indiviual list. Please note that the individual lists can also be of different sizes.
{
cin>>a;
list2.push_back(a);
}
list1.push_back(list2);
}
cout<<"your values:"<<endl;
for(auto i1=list1.begin();i1!=list1.end();i1++)
{
list<int>& list2=*i1;
for(auto j=list2.begin();j!=list2.end();j++)
{
cout<<*j<<" ";
}
cout<<endl;
}
return 0;
}
Here, we have used the auto
keyword, which assigns a data-type to the variable according to the value assigned to it, and thus, saving us the work to explicitly stating it. But, for learning's sake, please note that the data-type of j
in the above code is list<int>:: iterator
.
Quick question:
Which is the data-type of the variable 'i1' in the above code?
list <list <int>>:: iterator
.
Sorting of 2-D Lists
Sorting in two dimensional lists is a tricky task. Before we begin, let use see the working of the std::list::sort()
function for one dimensional lists.
Suppose we have to sort a 1-D list list1
, then, using this inbuilt sort function will look like this-
list1.sort();
The sort function sorts the elements in ascending order, by default. If you'd like the largest element first, then, we pass the greater<int>()
element as a parameter in the sort function. Ex.
list1.sort(greater<int>());
Time Complexity of sort()
is O(nlogn).
Now, coming to sorting of 2-D lists, there are multiple scenarios possible, such as
- Sorting individual list elements of the 2-D list.
- Sorting the entire 2-D list by comparing elements from individual lists
- Sorting the 2-D list according to the value of its elements present at a particular index, like the second value in every list. This is analogous to sorting with reference to a particular column in a 2-D array.
Let us explore each of these scenarios one by one.
1. Sorting individual list elements of the 2D list
When each individual list in the 2-D list is to be sorted, we iterate through the list, and call the sort()
function for every individual element.This is analogous to row-wise sorting in 2-D vectors.
Code:
//Here, list1 is our 2-D list.
for(auto i1=list1.begin();i1!=list1.end();i1++)
{
list<int>& list2=*i1;
list2.sort();
}
So, a list list <list <int>> list2= {{3,2,4},{7,2},{5,3,1}};
will get sorted as
{
{2,3,4},
{2,7},
{1,3,5}
}
2. Sorting the entire 2-D list by comparing elements from individual lists
In this scenario, the elements of the lists are compared one by one, and the lists are arranged in increasing order. This is a straight-forward case which can be achieved by using the sort()
function directly on the 2-D array. This can be implemented as-
//Here, list1 is our 2-D list.
list1.sort();
So,a list list <list <int>> list2= {{3,2,4},{7,2},{5,3,1}};
will get sorted as
{
{3,2,4},
{5,3,1},
{7,2}
}
If we can to sort the list in decreasing order, we pass the function greater< list<int>>()
as a parameter in the sort()
function, just like in case of 1-D arrays.
3. Sorting the 2-D list according to the value of its elements present at a particular index
This is analogous to sorting with reference to a particular column in a 2-D vector. For this, we will need to design a comparison function which returns a boolean value after comparing the values of the elements at a pre-specified index. For this, we shall use std::advance
, which advances the iterator by a given distance. It takes two parameters- the input operator and the number of iterations to be done.
Let us now code the comparison function:
bool compareval(const list<int>& l1,const list<int>& l2 ) {
auto a = l1.begin();
std::advance(a, 2);
auto b = l2.begin();
std::advance(b, 2);
return *a < *b;
}
//Here, 2 is the number we want the iterator to move ahead by. So, analogously it represents the column number of a 0-indexed vector.
In the main function, we call the sort function.
list <list <int>> list1= {{3,2,4},{7,2,0},{5,3,1}};
list1.sort(compareval);
In this case, the output will be:
{
{7,2,0},
{5,3,1},
{3,2,4}
}
//Take a look at how the last values of the 3 lists i.e. 0, 1, 4 are now sorted.
Before we end this discussion, here's a final question:
Will the order of the elements of the 2-D list change if we apply "row-wise" sorting?
With this article at OpenGenus, you must have the complete idea of 2D lists in C++. Enjoy.
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