Double Ended Queue (Deque)
Do not miss this exclusive book on Binary Tree Problems. Get it now for free.
Reading time: 25 minutes | Coding time: 10 minutes
A double ended queue also called as deque (pronounced as ‘deck’ or ‘dequeue’) is a list in which the elements can be inserted or deleted at either end in constant time. It is also known as a head-tail linked list because elements can be added to or removed from either the front (head) or the back (tail) end. However, no element can be added and deleted from the middle. In the computer’s memory, a deque is implemented using either a circular array or a circular doubly linked list. In a deque, two pointers are maintained, LEFT and RIGHT, which point to either end of the deque. The elements in a deque extend from the LEFT end to the RIGHT end and since it is circular, in a deque of N elements, Nth element of deque is followed by the first element of the deque.
There are two variants of a double-ended queue. They include:
- Input restricted deque: In this dequeue,insertions can be done only at one of the ends,while deletions can be done from both ends.
- Output restricted deque: In this dequeue,deletions can be done only at one of the ends,while insertions can be done on both ends.
Pseudocode
There are four basic operations in usage of Deque that we will explore:
- Insertion at rear end
- Insertion at front end
- Deletion at front end
- Deletion at rear end
Algorithm for Insertion at rear end
Step-1: [Check for overflow]
if(rear==MAX)
Print("Queue is Overflow”);
return;
Step-2: [Insert Element]
else
rear=rear+1;
q[rear]=no;
[Set rear and front pointer]
if rear=0
rear=1;
if front=0
front=1;
Step-3: return
Algorithm for Insertion at front end
Step-1 : [Check for the front position]
if(front<=1)
Print("Cannot add item at the front”);
return;
Step-2 : [Insert at front]
else
front=front-1;
q[front]=no;
Step-3 : Return
Algorithm for Deletion from front end
Step-1 [ Check for front pointer]
if front=0
print(" Queue is Underflow”);
return;
Step-2 [Perform deletion]
else
no=q[front];
print(“Deleted element is”,no);
[Set front and rear pointer]
if front=rear
front=0;
rear=0;
else
front=front+1;
Step-3 : Return
Algorithm for Deletion from rear end
Step-1 : [Check for the rear pointer]
if rear=0
print(“Cannot delete value at rear end”);
return;
Step-2: [ perform deletion]
else
no=q[rear];
[Check for the front and rear pointer]
if front= rear
front=0;
rear=0;
else
rear=rear-1;
print(“Deleted element is”,no);
Step-3 : Return
Complexity
- Insertion or deletion in the middle is O(n)
- The time complexity of random access by index is O(1)
- time complexity of all enque(insert)/deque(delete) operations is O(1)
Implementations
#include <iostream>
using namespace std;
#define MAX 10
int deque[MAX];
int leftt =-1 ;
int rightt = -1 ;
void inputdeque(void);
void outputdeque(void);
void insertleft(void);
void insertright(void);
void deleteleft(void);
void deleteright(void);
void display(void);
int main( )
{
int option;
cout<<"\n ----MAIN MENU----";
cout<<"\n 1.Input restricted deque";
cout<<"\n 2.Output restricted deque";
cout<<"\n Enter your option : ";
cin>>option;
switch (option)
{
case 1: inputdeque();
break;
case 2: outputdeque();
break;
} return 0;
}
void inputdeque( )
{
int option;
do
{
cout<<"\n\n INPUT RESTRICTED DEQUE";
cout<<"\n 1.Insert at right";
cout<<"\n 2.Delete from left";
cout<<"\n 3.Delete from right";
cout<<"\n 4.Display";
cout<<"\n 5.Quit";
cout<<"\n Enter your option : ";
cin>>option ;
switch (option)
{
case 1: insertright();
break;
case 2: deleteleft();
break;
case 3: deleteright();
break;
case 4: display();
break;
}
} while (option!=5);
}
void outputdeque( )
{
int option;
do
{
cout<<"\n\n OUTPUT RESTRICTED DEQUE";
cout<<"\n 1.Insert at right";
cout<<"\n 2.Insert at left";
cout<<"\n 3.Delete from left";
cout<<"\n 4.Display";
cout<<"\n 5.Quit";
cout<<"\n Enter your option : ";
cin>>option ;
switch(option)
{
case 1: insertright();
break;
case 2: insertleft();
break;
case 3: deleteleft();
break;
case 4: display();
break;
}
}while (option!=5);
}
void insertright( )
{
int val;
cout<<"\n Enter the value to be added:" ;
cin>>val;
if ( (leftt == 0 && rightt == MAX-1 ) || (leftt == rightt+1) )
{
cout<<"\n OVERFLOW";
return;
}
if (leftt == -1) // Queue is Empty Inititally
{
leftt = 0;
rightt = 0;
}
else
{
if (rightt == MAX-1) //right is at last position of queue
rightt = 0;
else
rightt = rightt+1;
}
deque[rightt] = val ;
}
void insertleft( )
{
int val;
cout<<"\n Enter the value to be added:";
cin>>val;
if( (leftt ==0 && rightt == MAX-1) || (leftt == rightt+1) )
{
cout<<"\n OVERFLOW";
return;
}
if (leftt == -1) //If queue is initially empty
{
leftt = 0;
rightt = 0;
}
else
{
if(leftt == 0)
leftt = MAX - 1 ;
else
leftt = leftt - 1 ;
}
deque[leftt] = val;
}
void deleteleft( )
{
if ( leftt == -1 )
{
cout<<"\n UNDERFLOW";
return ;
}
cout<<"\n The deleted element is : "<< deque[leftt];
if (leftt == rightt)
{
leftt = -1 ;
rightt = -1 ;
}
else
{
if ( leftt == MAX - 1 )
leftt = 0;
else
leftt = leftt+1;
}
}
void deleteright()
{
if ( leftt == -1 )
{
cout<<"\n UNDERFLOW";
return ;
}
cout<<"\n The element deleted is : "<< deque[rightt];
if (leftt == rightt)
{
leftt = -1 ;
rightt = -1 ;
}
else
{
if (rightt == 0)
rightt = MAX - 1 ;
else
rightt = rightt - 1 ;
}
}
void display( )
{
int front = leftt, rear = rightt;
if ( front == -1 )
{
cout<<"\n QUEUE IS EMPTY";
return;
}
cout<<"\n The elements of the queue are : ";
if (front <= rear )
{
while (front <= rear)
{
cout << deque[front] <<" ";
front++;
}
}
else
{
while (front <= MAX - 1)
{
cout << deque[front] <<" ";
front++;
}
front = 0;
while (front <= rear)
{
cout<< deque[front]<<" ";
front++;
}
}
cout<<endl;
}
Applications
- Palindrome Checker
- A-Steal job scheduling algorithm
- The A-Steal algorithm implements task scheduling for several
processors(multiprocessor scheduling).- The processor gets the first element from the deque.
- When one of the processor completes execution of its own
threads it can steal a thread from another processor.
- It gets the last element from the deque of another processor
and executes it.
Can Deque be implemented as a purely functional data structure?
Sign up for FREE 3 months of Amazon Music. YOU MUST NOT MISS.