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Semaphore in C

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Semaphore is a data handling technique which is very useful in process synchronization and multithreading. In this article, we will explore how we can use semaphore in C language.

We have the POSIX semaphore library in Linux systems. We will use this in our case.

The basic code of a semaphore cannot be typed directly into client code as it should be atomic and writing code directly would lead to a context switch which would lead to unexpected results.

The POSIX system in Linux presents its own built-in semaphore library. To use it, we have to :

  • Include semaphore.h header file
  • Compile the code by linking with -lpthread -lrt

To lock a semaphore, we can use the sem_wait function:

int sem_wait(sem_t *sem);

To release or signal a semaphore, we use the sem_post function:

int sem_post(sem_t *sem);

A semaphore is initialised by using sem_init (for processes or threads) or sem_open (for Interprocess communication).

sem_init(sem_t *sem, int pshared, unsigned int value);

sem : Specifies the semaphore to be initialized.
pshared : This argument specifies whether or not the newly initialized semaphore is shared between processes or between threads. A non-zero value means the semaphore is shared between processes and a value of zero means it is shared between threads.
value : Specifies the value to assign to the newly initialized semaphore.

To destroy a semaphore, we can use sem_destroy.

sem_destoy(sem_t *mutex);

To declare a semaphore, the data type is sem_t.

#include < stdio.h> 
#include < pthread.h> 
#include < semaphore.h> 
#include < unistd.h> 
sem_t mutex; 
void* thread(void* arg) 
    printf("\nEntered thread\n"); 
    //critical section 
    printf("\n Exit thread\n"); 
int main() 
    sem_init(&mutex, 0, 1); 
    pthread_t t1,t2; 
    return 0; 

Compilation should be done with gcc a.c -lpthread -lrt

Explanation of above code

2 threads are being created, one 2 seconds after the first one.
The first thread will sleep for 4 seconds after acquiring the lock.
Thus the second thread will not enter immediately after it is called, it will enter 4 – 2 = 2 secs after it is called.

So the output is:

Entered thread
Exit thread

Entered thread
Exit thread

If we would not have used semaphore, the output would have been as follows due to context switching:

Entered thread
Entered thread
Exit thread
Exit thread
OpenGenus Tech Review Team

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